Geometric
Probability mass function
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Cumulative distribution function
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المتغيرات
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Support
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Probability mass function (pmf)
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Cumulative distribution function (cdf)
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Mean
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Median
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(not unique if is an integer)
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(not unique if is an integer)
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Mode
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Variance
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Skewness
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Excess kurtosis
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Entropy
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Moment-generating function (mgf)
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, for
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Characteristic function
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التوزيع الهندسي Geometric distribution وهوجزء من التوزيع الاحتمالي الغير متعلق بمحاولات برنولي Bernoulli trials.
ويستخدم التوزيع الهندسي كم عدد المحاولات التي نحتاجها للحصول على النتيجة المطلوبة
مثال ليكن لدينا نرد متجانس (1,2,3,4,5,6,) كم عدد المحاولات (n) التي نحتاجها للحصول على الرقم 6
الحل :
الاحتمال السليم P = 1/6
الاحتمالات الخاطئة q=1-P = 5/6
العزوم والتراكمات
The expected value of a geometrically distributed random variable X is 1/p and the variance is (1 − p)/p2:
Similarly, the expected value of the geometrically distributed random variable Y is (1 − p)/p, and its variance is (1 − p)/p2:
Let μ = (1 − p)/p be the expected value of Y. Then the cumulants of the probability distribution of Y satisfy the recursion
Outline of proof: That the expected value is (1 − p)/p can be shown in the following way. Let Y be as above. Then
(The interchange of summation and differentiation is justified by the fact that convergent power series converge uniformly on compact subsets of the set of points where they converge.)
خواص أخرى
- The probability-generating functions of X and Y are, respectively,
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Golomb coding is the optimal prefix code for the geometric discrete distribution.
توزيعات ذات صلة
- The geometric distribution Y is a special case of the negative binomial distribution, with r = 1. More generally, if Y1, ..., Yr are independent geometrically distributed variables with parameter p, then the sum
- follows a negative binomial distribution with parameters r and '1-'p.
- If Y1, ..., Yr are independent geometrically distributed variables (with possibly different success parameters pm), then their minimum
- is also geometrically distributed, with parameter
- Suppose 0 < r < 1, and for k = 1, 2, 3, ... the random variable Xk has a Poisson distribution with expected value r k/k. Then
- has a geometric distribution taking values in the set {0, 1, 2, ... , with expected value r/(1 − r).
- The exponential distribution is the continuous analogue of the geometric distribution. If X is an exponentially distributed random variable with parameter λ, then
- where
انظر أيضاً
- توزيع هندسي زائدي
- مشكلة جامع الكوبونات
الهامش
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^ http://www.wolframalpha.com/input/?i=inverse+p+%3D+1+-+e^-l
وصلات خارجية
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Geometric distribution على بلانيت ماث
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Geometric distribution on MathWorld.
- Online geometric distribution calculator
نطقب:Common univariate probability distributions